Question

Consider a general reaction enzyme A(aq) ? B(aq) The ?G'° of the reaction is ?6.010 kJ · mol?1. Calculate the equilibrium constant for the reaction at 25 °C. K'eq = What is ?G for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.55 M? ?G = kJ · mol?1

          Consider a general reaction
enzyme
A(aq) ? B(aq)
The ?G'° of the reaction is ?6.010 kJ · mol?1. Calculate the equilibrium constant for the reaction at 25 °C.
K'eq =
What is ?G for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.55 M?
?G = kJ · mol?1

Consider a general reaction
enzyme
A(aq) ? B(aq)
The ?G'° of the reaction is ?6.010 kJ · mol?1. Calculate the equilibrium constant for the reaction at 25 °C.
K'eq =
What is ?G for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.55 M?
?G = kJ · mol?1

Added by Kim D.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Derrick Danso

Step 1

ΔG°' = -RT ln(K_eq) Where ΔG°' is the standard Gibbs free energy change, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C + 273.15 = 298.15 K), and K_eq is the equilibrium constant. 6.010 kJ/mol = 6010 J/mol Now, we can rearrange the Show more…

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Consider a general reaction: A(aq) ⇌ B(aq) The ΔG'° of the reaction is −6.010 kJ · mol−1. Calculate the equilibrium constant for the reaction at 25 °C. What is ΔG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is 0.55 M?