Question

QUESTION 5 Oxidation of glucose to carbon dioxide and water can occurs by combustion in the laboratory or by biological oxidation in living cells (see figure glucose degradation & synthesis in the slides). When combustion is carried out under controlled conditions, the reaction is highly exothermic, with an enthalpy change of -673 kcal/mol. The delta G for this reaction at 25 °C is -686 kcal/mol, so the reaction is also highly exergonic. a) (0.25 points) explain what the delta H and delta G values mean. What do the negative signs mean in each case? b) (0.25 points) without doing any calculations, would you expect delta S for this reaction to be positive or negative? Explain. c) (0.25 points) Now calculate the delta S for this reaction at 25° C. Does the calculated value agree in sign with your prediction in part b? d) (0.25 points) what are the values of delta G, delta H and delta S for the reverse reaction (synthesis of glucose)?

          QUESTION 5

Oxidation of glucose to carbon dioxide and water can occurs by combustion in the laboratory or by biological oxidation in living cells (see figure glucose degradation & synthesis in the slides). When combustion is carried out under controlled conditions, the reaction is highly exothermic, with an enthalpy change of -673 kcal/mol. The delta G for this reaction at 25 °C is -686 kcal/mol, so the reaction is also highly exergonic.

a) (0.25 points) explain what the delta H and delta G values mean. What do the negative signs mean in each case?

b) (0.25 points) without doing any calculations, would you expect delta S for this reaction to be positive or negative? Explain.

c) (0.25 points) Now calculate the delta S for this reaction at 25° C. Does the calculated value agree in sign with your prediction in part b?

d) (0.25 points) what are the values of delta G, delta H and delta S for the reverse reaction (synthesis of glucose)?

QUESTION 5

Oxidation of glucose to carbon dioxide and water can occurs by combustion in the laboratory or by biological oxidation in living cells (see figure glucose degradation synthesis in the slides). When combustion is carried out under controlled conditions, the reaction is highly exothermic, with an enthalpy change of -673 kcal/mol. The delta G for this reaction at 25 °C is -686 kcal/mol, so the reaction is also highly exergonic.

a) (0.25 points) explain what the delta H and delta G values mean. What do the negative signs mean in each case?

b) (0.25 points) without doing any calculations, would you expect delta S for this reaction to be positive or negative? Explain.

c) (0.25 points) Now calculate the delta S for this reaction at 25° C. Does the calculated value agree in sign with your prediction in part b?

d) (0.25 points) what are the values of delta G, delta H and delta S for the reverse reaction (synthesis of glucose)?

Added by Erik L.

Question

Please give Ace some feedback