Question

Find the interval of convergence of the series. sum_{n=0}^{infty} frac{(x-7)^n}{3n+3} 6 le x < 8 6 < x < 8 x < 8 4 le x < 10

          Find the interval of convergence of the series.

sum_{n=0}^{infty} frac{(x-7)^n}{3n+3}

6 le x < 8
6 < x < 8
x < 8
4 le x < 10

$Find the interval of convergence of the series. sumn=0^infty frac(x-7)^n3n+3 6 le x < 8 6 < x < 8 x < 8 4 le x < 10$

Added by Paula M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

07/28/2023

Step 1

To do this, we can use the ratio test: lim(n->∞) |(2/3n)/(2/3(n-1))| = lim(n->∞) |(2/3n)(3(n-1)/2)| = lim(n->∞) |(n-1)/n| = 1 Since the limit is equal to 1, the ratio test is inconclusive. We need to use another test to determine the interval of Show more…

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