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Question 8 Consider the function $f(x) = x^{-3}$. It can be shown that the derivative of $f$ is $f'(x) = -3x^{-4}$. Find $L(x)$, the local linearization of $f$ at $a = -4$. Note that $L(x)$ is also a function whose graph is the tangent line at $a = -4$. $L(x) = $

          Question 8
Consider the function $f(x) = x^{-3}$. It can be shown that the derivative of $f$ is $f'(x) = -3x^{-4}$.
Find $L(x)$, the local linearization of $f$ at $a = -4$. Note that $L(x)$ is also a function whose graph is the
tangent line at $a = -4$.
$L(x) = $

Question 8
Consider the function f(x) = x^-3. It can be shown that the derivative of f is f'(x) = -3x^-4.
Find L(x), the local linearization of f at a = -4. Note that L(x) is also a function whose graph is the
tangent line at a = -4.
L(x) =

Added by Joel R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

10/21/2023

Step 1

Step 1: The local linearization of a function f(x) at a point x = a is given by: $L(x) = f(a) + f'(a)(x-a)$ Show more…

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Question 8 Consider the function $f(x) = x^{-3}$. It can be shown that the derivative of f is $f'(x) = -3x^{-4}$. Find $L(x)$, the local linearization of f at $a = -4$. Note that $L(x)$ is also a function whose graph is the tangent line at $a = -4$. L(x) = Check Answer