Question

What is the approximate mass of air in a living room 3.5 m x 4.6 m x 4.6 m ? density of air = 1.20 kg/m3 QUESTION 8 What is the absolute pressure on the bottom of a swimming pool 13.1 m by 12.3 m whose uniform depth is 3.9 m? g = 9.8 m/s2 density of water = 1000 kg/m3 Atmospheric pressure = 1.013 x 105 Pa Give the answerr in scientific notation. For example If your answer is 1.2 x 105 write 1.2e5

          What is the approximate mass of air in a living room 3.5 m x 4.6 m x 4.6 m ?

density of air = 1.20 kg/m3

QUESTION 8
What is the absolute pressure on the bottom of a swimming pool 13.1 m by 12.3 m whose uniform depth is 3.9 m?

g = 9.8 m/s2

density of water = 1000 kg/m3

Atmospheric pressure = 1.013 x 105 Pa

Give the answerr in scientific notation.
For example If your answer is 1.2 x 105 write 1.2e5

What is the approximate mass of air in a living room 3.5 m x 4.6 m x 4.6 m ?

density of air = 1.20 kg/m3

QUESTION 8
What is the absolute pressure on the bottom of a swimming pool 13.1 m by 12.3 m whose uniform depth is 3.9 m?

g = 9.8 m/s2

density of water = 1000 kg/m3

Atmospheric pressure = 1.013 x 105 Pa

Give the answerr in scientific notation.
For example If your answer is 1.2 x 105 write 1.2e5

Added by Khaled B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Pawan Yadav

04/01/2021

Step 1

This is given by the equation P = ρgh, where ρ is the density of the water, g is the acceleration due to gravity, and h is the height of the water column. Substituting the given values, we get P = 1000 kg/m^3 * 9.8 m/s^2 * 3.9 m = 3.822e4 Pa. However, this is Show more…

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QUESTION 8 What is the absolute pressure on the bottom of a swimming pool 13.1 m by 12.3 m whose uniform depth is 3.9 m? g = 9.8 m/s2 density of water = 1000 kg/m3 Atmospheric pressure = 1.013 x 105 Pa Give the answerr in scientific notation. For example If your answer is 1.2 x 105 write 1.2e5