A batch of 500 hard drives contains 12 defective ones. A sample of 20 of these hard drives is selected for testing. What is the probability that the sample will contain exactly 4 defective hard drives? 4 x C(12,4) / 500 C(488,16) x C(12,4) / C(500,20) C(500,20) / (C(488,16) x C(12,4)) 4 x 12/500
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This can be calculated using the binomial probability formula: C(12,4) * (0.02)^4 * (0.98)^16 Show more…
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