A particle moves along a line with a velocity v(t) = t^2 - 2t - 3, measured in meters per second. Find the total distance the particle travels from t = 0 seconds to t = 4 seconds.
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The integral of t^2 - 2t + 3 dt from 0 to 4 is [(t^3)/3 - t^2 + 3t] evaluated from 0 to 4. Show more…
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