00:01
One application for antiderivative is finding the area bounded by graphs.
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In this problem, we want to find the area that is bounded by the graphs of the following equation.
00:11
We have y equals x plus 2 and y equals x squared.
00:18
So for us to find the area, we have to draw the graphs of this function.
00:25
So for that, we have to find their intersection point.
00:28
So we will equate these two equations to find the values of x where these two, where the graphs of these two functions intersect.
00:38
So equating gives us x plus 2 equals x squared.
00:42
And we rearrange this equation to get x squared minus x minus 2 equals 0, which we can factor into x minus 2 times x plus 1 equals 0.
00:53
That gives us x equals 2 or x is equal to negative 1.
00:59
So these two graphs intersect at x equals 2 and x equals 1.
01:05
So if x is equal to 2, your y, using the first equation x plus 2 will be 2 plus 2 or that's equal to 4.
01:20
If x is equal to negative 1, you have y equals negative 1 plus 2 that uses 1...