Given that $\sin(\theta) = \frac{5}{13}$, and $\theta$ is in quadrant I, what is $\cos(\theta)$?
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Given that sin(\theta )=(5)/(13), we can use the Pythagorean identity to find cos(\theta ). Using the Pythagorean identity: sin^2(\theta ) + cos^2(\theta ) = 1 (5/13)^2 + cos^2(\theta ) = 1 25/169 + cos^2(\theta ) = 1 cos^2(\theta ) = 1 - 25/169 cos^2(\theta ) = Show more…
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