00:01
In this question, we're asked, we're told that the current in a circuit, in an rl circuit, with a certain voltage source and resistance and inductance is given by that differential equation.
00:13
We want to extract an equation for the current as a function of time.
00:18
So how do we do this? well, the hint says that we can treat this as a first order linear differential equation, where instead of saying that a of relying on this function as being y of x, will rely on this function as being i of t.
00:38
This over here, this r over l, is our function p of t, and our function q of t is equal to v over l.
00:53
Now remember that we can obtain the integrating factor we have to multiply from this equation, which is going to be the exponential of the integral of our function.
01:08
R over l d t, which would be equal to the exponential of rt over l.
01:30
Okay, so now we have to multiply this entire thing by, we have to multiply the integrating factor across the entire differential equation.
01:39
When we do that, we'll have e to the rt over l, d, i, dt, t, plus r over l times i times e to the rt over l, l will be equal to v over l times e to the rt over l.
02:06
The left -hand side is going to become the product rule, which is the time derivative of i times e to the rt over l, which is going to be equal to v over l times e to the rt over l.
02:26
And now that we have this, we can now integrate both sides with respect to t...