Question

Question: Two forces are represented by vectors $F_1 = 2i + 2j - k$ and $F_2 = 2i - 6j - 3k$. Find: \begin{itemize} \item dot product ($F_1 \cdot F_2$) \item the magnitude of obtuse angle between these two forces (in radians). \end{itemize}

          Question:
Two forces are represented by vectors $F_1 = 2i + 2j - k$ and $F_2 = 2i - 6j - 3k$. Find:
\begin{itemize}
    \item dot product ($F_1 \cdot F_2$)
    \item the magnitude of obtuse angle between these two forces (in radians).
\end{itemize}

Question:
Two forces are represented by vectors F1 = 2i + 2j - k and F2 = 2i - 6j - 3k. Find:

* dot product (F1 · F2)

* the magnitude of obtuse angle between these two forces (in radians).

Added by Robin S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Christopher Stanley

07/28/2022

Step 1

Step 1: To find the dot product of two vectors F₁ and F₂, we use the formula: F₁ * F₂ = (F₁x * F₂x) + (F₁y * F₂y) + (F₁z * F₂z) where F₁x, F₁y, F₁z are the components of vector F₁ and F₂x, F₂y, F₂z are the components of vector F₂. Show more…

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Question: Two forces are represented by vectors F₁ = 2i + 2j - k and F₂ = 2i - 6j - 3k. Find: dot product (F₁ * F₂) the magnitude of the obtuse angle between these two forces (in radians). Question: Two forces are represented by vectors F = 2i + 2j - k and F = 2i - 6j - 3k. Find: dot product (F₁ * F) the magnitude of the obtuse angle between these two forces (in radians).