Question Use the quotient rule to evaluate h'(a) for the given function h(x) and a. h(x) = - (6x^2) / (4x^2 + 6x - 10) a = 2 Enter an exact answer. h'(2) =
Added by Alex P.
Close
Step 1
If we have a function \( h(x) = \frac{f(x)}{g(x)} \), then the derivative of \( h(x) \), denoted as \( h'(x) \), is given by: \[ h'(x) = \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} \] Show more…
Show all steps
Your feedback will help us improve your experience
Sanchit Jain and 81 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Differentiate each function. (a) $h(w)=\frac{6}{\sqrt{w^{2}+4}}$ (b) $h(w)=\frac{\sqrt{w^{2}+4}}{6}$
Differentiation
The Chain Rule
Use the Quotient Rule to differentiate the function. $h(x)=\frac{\sqrt[3]{x}}{x^{3}+1}$
Product and Quotient Rules and Higher-Order Derivatives
Evaluate and simplify the difference quotient (f(x+h) - f(x))/h for the function where h ≠0. f(x) = x^2 - 6x
Julie S.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD