00:01
This problem, we first want to find a linearization.
00:06
So part 8, let f of x be equal to 1 plus x into the power k.
00:15
Find the linearization of our function f of x at x equals 0.
00:29
First we find the derivative of our function, and that's k times 1 plus x to the power of k.
00:35
Minus 1.
00:36
We're also told that k is some constant, well, it's not much more than the problem, but this assume k is some constant.
00:43
And the derivative of our function at 0, that's going to be k, is 1 plus 0 to the power of k minus 1.
00:51
So that's just simply k.
00:53
The linearization is l of x, which is the value of the function at 0 in this case, also derivative of our function at 0 times x minus 0.
01:04
So l of x the linearization would be f of 0 and from our function f of 0 is going to be 1 plus 0 to the power of k, which is 1 to the k power which is 1.
01:17
So this would be 1 plus the derivative of our function 0 which is k times x minus 0, which is simply k.
01:25
So that's the first part of the problem to show that the linearization is 1 plus k x.
01:30
For part b, now we are asked to use the linear approximation, use the fact that 1 plus k, sorry, 1 plus x to the power of k, that's better, is approximately equal to 1 plus kx.
01:55
And that's pretty much what part a was all about...