QUESTION 34 The carbon contents of ferrite (?), pearlite and cementite (Fe3C) are 0.022 wt%, 0.77 wt% and 6.70 wt%, respectively. With the aid of Figure 15: (a) Calculate the proportion of pearlite in the microstructure of 0.4 wt% C steel just below the eutectoid temperature (727 °C). Show all the necessary working. (5 marks) (b) List one possible application for this type of steel and briefly explain the basis of your choice. (3 marks)
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4 wt% C steel just below the eutectoid temperature, we will use the lever rule. The lever rule is a tool used to determine the fraction of each phase in a two-phase system. It is based on the conservation of mass and the concept that the total amount of a component Show more…
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A 0.80 percent C eutectoid plain-carbon steel is slowly cooled from 750°C to a temperature just slightly below 727°C. Assuming the austenite is completely transformed to alpha ferrite and cementite: (Use Iron-Iron carbide phase diagram, Figure 10.28 page 420 in your book) or see fig below: Calculate the approximate weight percent eutectoid cementite formed. a) 5% b) 12% c) 17% d) 21%
For a 0.3 wt%C carbon steel, the microstructure consisted of a mixture of ferrite and pearlite (e.g. ferrite and cementite) phases. Calculate the amount of pro-eutectoid ferrite, pearlite, and cementite phases in this steel. (Data: Maximum solid solubility of ferrite at the eutectoid temperature is 0.022 wt.% C. The eutectoid composition is 0.76 wt.% and the composition of cementite is 6.7 wt.% C).
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