Question 5 Write down the equilibrium points of the following system of differential equations. x'(t) = 4x - x^2 - 4xy y'(t) = 3y - 2y^2 - xy
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For the first equation, r'(1) = 4x - x^2 - 40, setting it equal to zero gives us: 4x - x^2 - 40 = 0 For the second equation, y'(1) = 3y - 2y^2 - x, setting it equal to zero gives us: 3y - 2y^2 - x = 0 Now we have a system of two equations: 4x - x^2 - 40 = 0 3y Show more…
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