R is a ring, prove that if a, b E R, then (a + b)^2 = a^2 + ab + ba + b^2 , where by x^2 we mean xx.
Added by Christopher H.
Step 1
Using the distributive property, we get: (a + b)^2 = (a + b)(a + b) Now, we distribute (a + b) to both a and b: = a(a + b) + b(a + b) Show more…
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