00:01
Okay, so the net rate of heat loss is equal to the difference between the initial rate of heat loss and the final rate of heat loss, which is q1 over delta t minus q2 over dlt.
00:11
So therefore we eventually have h -net, which is a net rate of heat loss, is equal to e sigma times a and times t1 to the power 4 minus t2 to the power 4.
00:21
E is the invisivity.
00:22
Sigma is the stefan bousman constant.
00:25
And the a is the service area of a cylinder.
00:28
Okay.
00:30
And t1 is the initial temperature and t2 is a final temperature.
00:34
So when the imissivity is given at 0 .95 and the stephan -bozum constant is 5 .67 times 10 .08 watts per meter square times kelvin to a power 4.
00:44
T1, which is initial temperature, is given as 35 degrees celsius.
00:47
If we converted to kelvin, it's 308 kelvin.
00:52
And t2 is 5 degrees celsius, which is final temperature.
00:56
And if we convert it to kelvin, it's 278 kelvin...