00:01
So for this question, first we need to consider the stability of the carbocardion.
00:07
So first and first, option 5 would be correct for this question.
00:10
So e would be most reactive and c will be less reactive.
00:16
So among these alkaliites and for the most reactive sn2 reaction, there are two things which we need to focus on.
00:27
First is the stability of the carbonate ion and second is it should be less crowded.
00:32
So in the case of sn2 reaction, the stability, for sn2 reaction, the carbocatin, primary carbureyton should be more stable followed by secondary and tertiary carbocyanes.
00:45
And for sn2 reaction or in an sn2 reaction, the nucleophilic substitution will take place at the least crowded carbon atom.
00:57
So let's first consider the case of e alkanolite.
01:03
So we can see that here we have a primary carbocatan and this primary carburetion is least crowded...