00:01
Hi, in this question, k catalyst value has been given, michaelis -menten constant has been given, what would be concentration of substrate at 1 quarter maximum rate? so, michaelis -menten equation is v equal to vmax into concentration of substrate by 1 substrate concentration plus km and here rate is 1 quarter of maximum rate.
00:25
So, v is equal with vmax by 4 equal to vmax substrate concentration by substrate concentration plus 0 .0050.
00:39
Vmax vmax will be cancelled out.
00:42
So, s concentration plus 0 .0050 equal to 4 s substrate concentration is equal with 0 .0050 by 4 equal to 1 .25 into 10 to the power minus 3 molar.
01:04
Next, we need to find out fraction of vmax when concentration of substrate is half km.
01:10
For michaelis -menten equation, it is equation 1, fraction of vmax is v by vmax.
01:19
V is equal with substrate concentration by substrate concentration plus km, half km plus 1 plus half that is 3 by 2 km.
01:31
This and this will be cancelled out equal to 1 by 3...