Required information Two metal spheres of radius 5.00 cm carry net charges of +1.30 µC and +0.500 µC. Why cannot Coulomb's law be used to find the force of repulsion when their centers are 12.0 cm apart?
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Step 1: Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Show more…
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Two metal spheres of radius $5.0 \mathrm{cm}$ carry net charges of $+1.0 \mu \mathrm{C}$ and $+0.2 \mu \mathrm{C} .$ (a) What (approximately) is the magnitude of the electrical repulsion on either sphere when their centers are $1.00 \mathrm{m}$ apart? (b) Why cannot Coulomb's law be used to find the force of repulsion when their centers are $12 \mathrm{cm}$ apart? (c) Would the actual force be larger or smaller than the result of using Coulomb's law with $r=12 \mathrm{cm} ?$ Explain.
Two metal spheres of radius $5.0 \mathrm{~cm}$ carry net charges of $+1.0 \mu \mathrm{C}$ and $+0.2 \mu \mathrm{C}$. (a) What (approximately) is the magnitude of the clectrical repulsion on either sphere when their centers are $1.00 \mathrm{~m}$ apart? (b) Why cannot Coulomb's law be used to find the force of repulsion when their centers are $12 \mathrm{~cm}$ apart? (c) Would the actual force be larger or smaller than the result of using Coulomb's law with $r=12 \mathrm{~cm}$ ? Explain.
Two spheres with uniform surface charge density, one with a radius of 7.0 cm and the other with a radius of 5.0 cm, are separated by a center-to-center distance of 38 cm. The spheres have a combined charge of +55 μC and repel one another with a force of 0.62 N. Assume that the charge of the first sphere is greater than the charge of the second sphere. What is the surface charge density on the sphere of radius 7.0? What is the surface charge density on the second sphere? Please answer in units C/m2
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