Question

Resistors in a series with resistance R1 = 100Ω, R2 = 500Ω, and R3 = 100Ω are connected to a battery. The power through the R2 = 500Ω resistor is 100W. a) Voltage in the battery b) Power through the circuit c) Current going out of the battery d) Current through R1 e) Current through R2 f) Current through R3 g) Power through R1 h) Power through R3

Name: resistors in a series with resistance r1100 r2500 and r3100 are connected to a battery the power through the r2500 resistor is 100w a voltage in the battery bpower through the circuit c curr 65937
Uploaded: 2022-08-20T04:57:08-08:00
Duration: 3 min 14 s
Channel: Khoobchandra Agrawal
Description: resistors in a series with resistance r1100 r2500 and r3100 are connected to a battery the power through the r2500 resistor is 100w a voltage in the battery bpower through the circuit c curr 65937

          Resistors in a series with resistance R1 = 100Ω, R2 = 500Ω, and R3 = 100Ω are connected to a battery. The power through the R2 = 500Ω resistor is 100W.
a) Voltage in the battery
b) Power through the circuit
c) Current going out of the battery
d) Current through R1
e) Current through R2
f) Current through R3
g) Power through R1
h) Power through R3

Added by Kevin M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

08/20/2022

Step 1

Given resistances: \(R1 = 100\Omega\), \(R2 = 500\Omega\), \(R3 = 100\Omega\) Power through \(R2 = 100W\) Using the formula for power: \(P = I^2 \times R\) Given power through \(R2 = 100W\) and \(R2 = 500\Omega\) \(100 = I^2 \times 500\) \(I = 0.447A\) Total Show more…

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Resistors in a series with resistance R1 = 100Ω, R2 = 500Ω, and R3 = 100Ω are connected to a battery. The power through the R2 = 500Ω resistor is 100W. a) Voltage in the battery b) Power through the circuit c) Current going out of the battery d) Current through R1 e) Current through R2 f) Current through R3 g) Power through R1 h) Power through R3