00:01
Taking laplace transform of the circuit.
00:20
So according to the diagram, that's what 1 upon s, ohm, 1 ohm and apply kcl at node 1, that's for node 1.
00:28
So, v1 minus v at 1 minus vs into s upon 1 plus upon 1 upon s plus v1 upon 1 plus 1 upon s is equal to 0.
00:49
So, v1 is equal to 1 plus s plus s upon s plus 1 is equal to vs into s.
01:00
So, v1 is equal to s plus 1 upon s square plus 3s plus 1.
01:10
Vs into s.
01:12
And this is equation first.
01:14
So from the circuit, v0s is equal to 1 upon 1 plus 1 upon s.
01:25
So substituting v1, v0s is equal to s upon s plus 1 into s plus 1 upon s square plus 3s plus 1 into vs into s...