Question

An amusement park ride drops the occupants from rest at a height of 30m, then brings them to a soft landing before resting on the ground, what is the ride's top speed if it is allowed to free-fall 2/3rds of the way down? -20\frac{m}{s} -392\frac{m}{s} -24.7\frac{m}{s} -9.81\frac{m}{s}

          An amusement park ride drops the occupants from rest at a height of 30m, then brings them to a soft landing before resting on the ground, what is the ride's top speed if it is allowed to free-fall 2/3rds of the way down?
-20\frac{m}{s}
-392\frac{m}{s}
-24.7\frac{m}{s}
-9.81\frac{m}{s}

An amusement park ride drops the occupants from rest at a height of 30m, then brings them to a soft landing before resting on the ground, what is the ride's top speed if it is allowed to free-fall 2/3rds of the way down?
-20(m)/(s)
-392(m)/(s)
-24.7(m)/(s)
-9.81(m)/(s)

Added by Michelle M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

06/15/2022

Step 1

Since we're dealing with free fall and need to find the top speed, we'll use conservation of energy or kinematics equations. For this problem, we can use v² = u² + 2as, where v is final velocity, u is initial velocity, a is acceleration, and s is displacement. Show more…

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