00:01
Okay, so first we need to solve this.
00:04
Mine y, c, that is just m plus 1 squared.
00:13
So y equals c1, e to the minus x plus c2, x, e to the minus x.
00:23
Because you got repeated root of negative 1.
00:28
That's yc.
00:30
So then yp will be u1, e to the minus x, plus u2x, x, e to the minus x.
00:39
So we have to find u1 and u2.
00:42
Okay, first we've got to find the ronsky and w.
00:46
So use this in the first column, e to the minus x, and it's derivative minus e to the minus x.
00:54
Put this in the second column, x, e to the minus x.
00:58
And then it's derivative x, e to the minus x, first times the derivative of the second, plus the second times the derivative of the first.
01:12
So factor out an e to the minus x, and you get minus x plus one, or one minus x, e to the minus x.
01:24
So one minus x, e to the minus 2x, minus x e to the minus 2x, so e to the minus 2x, minus 2x, minus x, e to the minus 2x, plus x e to the minus 2x.
01:43
That is e to the minus 2x.
01:45
Okay, that's w.
01:52
Okay, so then u1 prime will be just like w, except for put zero in the first place, and this right here in the second place, x to the minus 4, e to the minus, and then copy this column, and then all of that over the wrong skin.
02:20
So 0 minus x to the minus 3, e to the minus 2x over e to the minus 2x.
02:36
So negative x to the minus 3...