00:01
Okay, so this is the graph i drew for this question.
00:03
So the force externally on the rider from the roller coaster seat should be the normal force here, which is in here.
00:13
As you can tell, the gravity of the riders plus the normal force from the roller coaster seat is equal to the centripetal force.
00:22
So now if you do time arrangement here, we have the normal force is equal to mv square over r minus m g, which is equal to m times v square of r minus g.
00:32
So we know the mass of the rider is 60 kilograms and the speed is 9 .7 meter per second.
00:39
And the radius of the loop is 6 .3 meter and the acceleration of gravity is equal to 9 .8 meter per second square.
00:46
So now we can plug in these values bank into the equation.
00:49
So we have normal force is equal to 60 kilograms times 9 .7 meter per second to the power 2 over 6 .3 meter minus.
01:03
9 .8 meter per second square.
01:07
And this will give us the normal force, which is the force exerted by the roller coaster seat, is equal to 308 newton...