Rod ab can slide freely along the floor and the inclined...

rod AB can slide freely along the floor and the inclined plane. At the instant shown, the velocity of end A is 2.93 m/s to the left. Determine the magnitude of the velocity of point B relative to that of point A in m/s.

Transcript

00:01 In this question we have given that the road a b can slide freely along the floor and the inclined plane.

00:06 We have given that the velocity of the end a is 2 .3 meter per second to the left.

00:14 Then we have to determine the velocity of end b of the road relative to a.

00:22 If we draw the diagram for this case, we have given that this is the in flying and this is a road this is the road placed now this is the point b this is point a and we have given that this point is moving in this in the left direction that the speed of this point is v a we can say that this is point v and b is moving in this direction this is the velocity of point b that is v b and we can say this is the velocity of little velocity that is b ab now let this angle is theta so we can say that this angle is 90 minus theta and let this angle is alpha we have given that this height is 300 m m and this site is 500 mm and this wall is 125 mm this angle is also alpha so first we have to find all these angles for that we can say that this is point this is point a this is b this point is c and this is point d in triangle d b b c we can say that their alpha is 10 inverse 300 upon 125 and that will 67 .4 degrees similarly in triangle a b c 3 .15 is sine invert 300 upon 500 so this will comes out 36 .870 this is the value of theta and this is the value of alpha now we can say that the velocity of point a on the link is leftward and the velocity of the point b on the link is there is downward along the slant plane so we can say that the relative velocity of point a with respect to b is in this direction that is perpendicular to the link ab so using sign rule we can say that the velocity of d with respect to a upon this is sine alpha that is equal to velocity of a upon this is sine 180 minus 90 plus theta so 90 minus theta plus alpha so you can say that this is vab is equal to this is va into sine alpha upon cost alpha minus theta if we put the value in this equation so this is 2 .3 into sine this is 67 .4 upon cost 67 .4 minus theta is 36 .37 .87.

05:29 This will come out 2 .474 1 meter per second...

Question

rod AB can slide freely along the floor and the inclined plane. At the instant shown, the velocity of end A is 2.93 m/s to the left. Determine the magnitude of the velocity of point B relative to that of point A in m/s.

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