Nine percent of U.S. employees who are late for work blame oversleeping. You randomly select four U.S. employees who are late for work and ask them whether they blame oversleeping. The random variable represents the number of U.S. employees who are late for work and blame oversleeping. Find the mean of the binomial distribution. ? = .360 (Round to the nearest hundredth as needed.) Find the variance of the binomial distribution. ?² = (Round to the nearest hundredth as needed.)
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We are given that there are 5096 employees who work part-time for economic reasons out of a total of 120 employees. So, the probability is: P = \frac{5096}{120} Now, we need to find the probability of exactly 14 employees working part-time for economic reasons Show more…
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