s_1^4 2-sqrt(t) / t^2 dt The text provided contains a few errors: 1. The integral symbol is not properly formatted. It should be a standard integral symbol, not "s_1^4". 2. The square root symbol is not properly closed. It should be "sqrt(t)" instead of "sqrt t". 3. The division symbol "/" should be replaced with a horizontal fraction bar for clarity. 4. The dt at the end of the integral should be separated from the integrand by a space. The corrected text should read: ∫[2 - √(t)] / t^2 dt from 1 to 4 Please note that I have only corrected the formatting and presentation errors. The actual evaluation of the integral is not provided as per the instructions.
Added by Kendra F.
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The corrected integral is: ∫[2 - √(t)] / t^2 dt from 1 to 4 Show more…
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