00:01
Here in this question we have got the data for the normal distribution with a mean of 44 ,000 and the standard deviation is 5 ,700.
00:13
So let us assume that xbd i'll refer the teacher and the given data is for mean is equal to 44 ,000 and number of teachers that are selected for this analysis is an is equal to 10 and standard deviation which is denoted by sigma is equal to 5 ,700.
00:38
Now let us assume a as the the 90 percentile, 90 percentile for an individual teacher salary.
00:50
So let's hear in this question we know the probability.
00:55
Now we need to calculate what is the salary for the teacher at the 90th percentile.
01:01
So let me write the probability equation.
01:04
P of x less than a is equal to p of z less than x minus mu by sigma.
01:13
So here z represents the z score value from the tables.
01:21
Probability we know that which is 90%, which is 0 .9...