A sample of size n = 100 is drawn from a normal population whose standard deviation is ? = 9.8. The sample mean is x? = 45.72. Part 1 of 2 (a) Construct a 90% confidence interval for ?. Round the answer to at least two decimal places. A 90% confidence interval for the mean is < ? < . Part 2 of 2 (b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain. The confidence interval constructed in part (a) (Choose one) be valid since the sample size (Choose one) large.
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The standard error is calculated as: SE = σ / √n where σ is the population standard deviation and n is the sample size. In this case, σ = 9.8 and n = 100. So, SE = 9.8 / √100 = 9.8 / 10 = 0.98 Show more…
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