5. [0/1 Points] DETAILS MY NOTES SCALCET9 5.3.019. PREVIOUS ANSWERS ASK YOUR TEACHER Use part one of the fundamental theorem of calculus to find the derivative of the func y = \int_{\sqrt{x}}^{\pi/6} \theta \tan(\theta) \,d\theta y' =
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Step 1: Recall that part one of the fundamental theorem of calculus states that if \(F(x) = \int_{a}^{x} f(t) dt\), then \(F'(x) = f(x)\). Show more…
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