Question

Sea $f(x) = \begin{cases} x^2 \cos(x) & \text{si } 0 \le x \le \frac{\pi}{2} \\ 2x & \text{si } \frac{\pi}{2} < x \le 2 \\ (2x - 1)^2 & \text{si } x > 2 \end{cases}$ \\ Entonces $\int_a^b f(x) dx$ cuyo límite inferior es 0 y superior 6

          Sea $f(x) = \begin{cases} x^2 \cos(x) & \text{si } 0 \le x \le \frac{\pi}{2} \\ 2x & \text{si } \frac{\pi}{2} < x \le 2 \\ (2x - 1)^2 & \text{si } x > 2 \end{cases}$ \\ Entonces $\int_a^b f(x) dx$ cuyo límite inferior es 0 y superior 6

Sea f(x) = x^2 cos(x) si 0 ≤ x ≤(π)/(2)
2x si (π)/(2) < x ≤ 2
(2x - 1)^2 si x > 2
Entonces ^b f(x) dx cuyo límite inferior es 0 y superior 6

Added by Jamie M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zack A

06/09/2023

Step 1

Step 1: The integral is $\int_0^6 f(x) dx$. Show more…

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Sea $f(x) = \begin{cases} x^2 cos(x) & si \ 0 \leq x \leq \frac{\pi}{2} \\ 2x & si \ \frac{\pi}{2} < x \leq 2 \\ (2x-1)^2 & si \ x > 2 \end{cases}$ Entonces $\int_a^b f(x) dx$ cuyo límite inferior es 0 y superior 6