Sec2.3: Problem 21 (1 point) Book Problem 43 A particle moves along a straight line and its position at time $t$ is given by $s(t) = 2t^3 - 27t^2 + 108t$ where $s$ is measured in feet and $t$ in seconds. a) Find the velocity (in ft/sec) of the particle at time $t = 0$: b) The particle stops moving twice, once when $t = A$ and again when $t = B$ where $A < B$. A is and B is c) What is the position of the particle at time 18? d) The TOTAL distance the particle travels between time 0 and time 18 is
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Step 1: To find the velocity of the particle at time t = 0, we need to find the derivative of the position function with respect to time. Show more…
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