Select the correct answer below that describes the two vectors given: r1(t) = (2+5t)i+(4-5t)j+(1+t)k r2(s) = (6+2s)i+(2-s)j+(7+3s)k These lines intersect at the point (2,4,1). These lines intersect at all points on the line . These lines are parallel. These lines are skew.
Added by Alex_Hags
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To do this, we can set the components of r1(t) equal to the components of r2(s) and see if there is a unique solution for t and s. (2+5t) = (6+2s) (4-5t) = (2-s) (1+t) = (7+3s) Solving the first equation for t, we get t = (2s+4)/5. Substituting this into the Show more…
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