00:02
Hi there.
00:03
In this question, we are looking for a set of four quantum numbers that could predict or could represent that last electron that is added to a nickel atom.
00:14
So to answer this, we need to talk first about the values that the orbital or that the quantum numbers can be.
00:21
Well, n is the principal quantum number, and that describes the energy level.
00:30
It can be any positive integer.
00:38
The next quantum number, l, is the angular one.
00:40
Momentum quantum number, and it describes the sub -shell.
00:45
It is also going to be an integer, but it's going to range from 0 to n minus 1.
00:56
So if n were 3, n minus 1 would be 2, an l could be 0, 1, or 2.
01:02
Furthermore, when l equals 0, that describes an s orbital.
01:06
When l equals 1, it's a p.
01:08
When l equals 2, it describes a d orbital, and when l equals 3, it would be in f orbit.
01:15
All right, the next quantum number, m sub l, is the magnetic quantum number.
01:20
It also is an integer, and it ranges from negative l to positive l.
01:29
So whatever l is, if l were three, m sub l could be negative three, negative two, negative one, zero, one, two, or three.
01:38
And finally, m sub s, that's the spin quantum number.
01:42
It refers to the electron and can be just one of two values.
01:46
Either positive one -half for a positive spin or negative one -half.
01:52
All righty.
01:53
So now we are working with nickel.
01:56
So let's look at our electron configuration, or abbreviated electron configuration for nickel.
02:02
Nickel's atomic number 28.
02:05
Therefore, i'm going to look at the period before nickel, which is the third period, and find the noble gas.
02:13
So by putting argon in brackets, that takes care of the first 18 core electrons.
02:19
And then we'll go across that fourth period until we get to nickel.
02:22
So that means we're going to fill in the 4s.
02:25
Then after the 4s comes the d, but remember d's, it's going to be the 3d...