00:01
5 students in the question moss of the benioic acid and 4 amino est of mar and then dimethyl teri thali in the first question we need to find out the mouse percentage and mole ratio of the given compounds for this question given 0 .1 to 1 gram of benzoic acid that is 0 .1 to 1 is divided with 122 .12 with smaller halves that gives 0 .99 multiplied with 10 to 3 moles.
00:49
104 gramma 4 amino converted into moles that if 135 .6 that gives 0 .76 is multiplied with 10 to 4 of minus 3 moles from the given sample and the flask weights 76 .872 grams this is the weight of the flask minus 76 .78 4 grams this is empty flaskol gives them 0 .08 grams of di -methyl tithel terry thallet it is converted into moles 0 .08 is divided with smaller mass 194 .186.
02:03
This is given 0 .453 multiplied with 10 to 4 of 3 moles.
02:12
This is the conversion of the given compounds into moles.
02:17
Therefore, mole ratio equal to 0 .99 multiplied with 10 % of 3, 0 .76 multiplied with 10 % of 3 0 .453 multiplied with 10 % of 3.
02:39
Benjoicase, this is 4 amino estophenone and this is dimethyl tarythalet this is the ratio by calculating this we are getting 99 each to 76 is to 45 .3 moles.
03:17
Therefore, mole ratio equal to 1 .3 mole is to 1 .6 .47 moles.
03:30
So mass percentage is 0 .1 to 1 to 0 .104 gram h to 0 .08 grams respectively benzic acid, estophenone and terethylate.
03:53
So total weight equal to 0 .313.
04:04
Therefore from this mass and the bone's ratio 0 .1 .313 equal to 38 .6%.
04:17
This is for banjoicassal.
04:21
In the same way, 0 .104 is divided with 0 .313, is for 33 .2 % is for 4 amino, estophenone.
04:41
And in the same way, 0 .088 is divided by 0 .313, is gives 28 .11.
04:53
This gives 28 .11.
04:54
This is...