Show all the work for full credit. (7 points) Problem 1. Find the general solution and a fundamental set of solutions of $x^2y'' - 3xy' + 3y = 0$, given that $y_1(x) = x$ is a solution. You are not allowed to use the general formula for $y_2(x)$ from the textbook.
Added by David W.
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The given differential equation is x^2y" - 3xy' + 3y = 0. To put it in standard form, we divide through by x^2: y" - (3/x)y' + (3/x^2)y = 0. Show more…
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