00:01
In the solution of a part, we need to find out probability for the second ball is red divided by the probability for first ball is red.
00:25
So here, as for the question, we are having first two possibilities as 10 by 16 for being blue and another 6 by 16 for red.
00:38
So in blue we have further probabilities for 6 by 15 when we have taken one ball.
00:47
And next is this is for red and for blue we have 9 out of 50.
00:54
And similarly for red we have another two.
00:58
First is for blue which is 10 by 50 and for red that is 6 by 15 here.
01:06
So from this observational study we can conclude here.
01:10
We will get second ball red that is 5 by 15 will be equal to 1 by 3 which is 0 .33.
01:24
3 3 so this is our required probability for the event a positive rate and here's the solution for a part of the question now our next part part b we have here probability for the second ball ball is blue divided by given first wall is red.
01:51
First fall is red.
01:55
This will be 10 divided by 40 which is equal to 557 is 0 .743...