Show that for every real number k the plane x - 2y + z + 3 + k(2x - y - z + 1) = 0 contains the line of intersection of the planes x - 2y + z + 3 = 0 and 2x - y - z + 1 = 0.
Added by Christopher E.
Step 1
To do this, we can solve the system of equations: x - 2y + z + 3 = 0 2x - y - z + 1 = 0 Multiplying the first equation by 2 and adding it to the second equation, we get: 4x - 5y + 1 = 0 Solving for x in terms of y, we get: x = (5y - 1)/4 Substituting this Show more…
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