Show that $\int_{(9,3)}^{(19,4)} fdx + gdy = \int_{(9,3)}^{(19,4)} -(45x^4y^4dx + 36y^3x^5dy)$ is independent of path: $\frac{\partial f}{\partial y} =$ $\frac{\partial g}{\partial x} =$ $\int_{(9,3)}^{(19,4)} -(45x^4y^4dx + 36y^3x^5dy) = $
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Step 1: First, let's define the functions f(x, y) and g(x, y) as follows: f(x, y) = 4y^3 g(x, y) = 9x^4 Show more…
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