Show that we have the following equality: \sqrt{det \begin{bmatrix} \vec{v}_1 \cdot \vec{v}_1 & \vec{v}_2 \cdot \vec{v}_1 \\ \vec{v}_1 \cdot \vec{v}_2 & \vec{v}_2 \cdot \vec{v}_2 \end{bmatrix}} = \sqrt{det \left( \begin{bmatrix} \vec{v}_1 \\ \vec{v}_2 \end{bmatrix} \cdot \begin{bmatrix} \vec{v}_1 & \vec{v}_2 \end{bmatrix} \right)}
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Step 1
Step 1: Let $\overrightarrow{v}_1 = \begin{bmatrix} x_1 \\ y_1 \end{bmatrix}$ and $\overrightarrow{v}_2 = \begin{bmatrix} x_2 \\ y_2 \end{bmatrix}$. Show more…
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