Question

Find the inverse of the matrix using the following formula $A^{-1} = \frac{1}{ad-bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix}$ $\begin{bmatrix} 2 & 3 \ -1 & 5 \end{bmatrix}$ Use an inverse matrix to solve the system of linear equations. $x_1 + x_2 - 2x_3 = 0$ $x_1 - 2x_2 + x_3 = 0$ $x_1 - x_2 - x_3 = -1$

          Find the inverse of the matrix using the following formula $A^{-1} = \frac{1}{ad-bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix}$
$\begin{bmatrix} 2 & 3 \ -1 & 5 \end{bmatrix}$
Use an inverse matrix to solve the system of linear equations.
$x_1 + x_2 - 2x_3 = 0$
$x_1 - 2x_2 + x_3 = 0$
$x_1 - x_2 - x_3 = -1$

Find the inverse of the matrix using the following formula A^-1 = (1)/(ad-bc)
< b m a t r i x >
< b m a t r i x >
Use an inverse matrix to solve the system of linear equations.
x1 + x2 - 2x3 = 0
x1 - 2x2 + x3 = 0
x1 - x2 - x3 = -1

Added by Juana W.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert William Mead

Step 1

To find the inverse of a 2x2 matrix, we can use the formula A^-1 = (1/det(A)) * adj(A), where det(A) is the determinant of A and adj(A) is the adjugate of A. First, let's find the determinant of A: det(A) = (2*5) - (3*1) = 10 - 3 = 7. Next, let's find the Show more…

Show all steps

Thanks for your feedback!

show work please a -b Find the inverse of the matrix using the following formula A-1 = ad-bc [ 2 3] 1 5 Use an inverse matrix to solve the system of linear equations x1 + x2 -2x3=0 x1 - 2x2 + x3 = 0 x1 - x2 - x3 = -1