\frac{(\cos 3\theta + i \sin 3\theta)(\cos \theta - i \sin \theta)}{(\cos \theta + i \sin \theta)^2}
Added by Sandra L.
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Step 1
First, let's simplify the expression inside the parentheses: cos 0 - i sin 0 = 1 - 0i = 1 cos 0 + i sin 0 = 1 + 0i = 1 Now, let's substitute these values back into the original expression: (cos 30 + i sin 30)(1)(1) Multiplying any number by 1 does not change its Show more…
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