Question

Does the series sum_{n=1}^{infinity} (-1)^n frac{sin n}{n^2} converge absolutely, converge conditionally, or diverge? Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. A. The series diverges per the Integral Test because int_{N}^{infty} f(x) dx does not exist. B. The series converges absolutely per the Direct Comparison Test of the series sum_{n=1}^{infty} frac{sin n}{n^2} with sum_{n=1}^{infty} frac{1}{n^2}. C. The series converges absolutely because the limit used in the Ratio Test is []. D. The series converges conditionally because the limit used in the nth-Term Test is []. E. The series diverges per the Alternating Series Test. F. The series converges conditionally because the corresponding series of absolute values is geometric with |r| = []

          Does the series sum_{n=1}^{infinity} (-1)^n frac{sin n}{n^2} converge absolutely, converge conditionally, or diverge?

Choose the correct answer below and, if necessary, fill in the answer box to complete your choice.

A. The series diverges per the Integral Test because int_{N}^{infty} f(x) dx does not exist.
B. The series converges absolutely per the Direct Comparison Test of the series sum_{n=1}^{infty} frac{sin n}{n^2} with sum_{n=1}^{infty} frac{1}{n^2}.
C. The series converges absolutely because the limit used in the Ratio Test is [].
D. The series converges conditionally because the limit used in the nth-Term Test is [].
E. The series diverges per the Alternating Series Test.
F. The series converges conditionally because the corresponding series of absolute values is geometric with |r| = []

$Does the series sumn=1^infinity (-1)^n fracsin nn^2 converge absolutely, converge conditionally, or diverge? Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. A. The series diverges per the Integral Test because intN^infty f(x) dx does not exist. B. The series converges absolutely per the Direct Comparison Test of the series sumn=1^infty fracsin nn^2 with sumn=1^infty frac1n^2. C. The series converges absolutely because the limit used in the Ratio Test is []. D. The series converges conditionally because the limit used in the nth-Term Test is []. E. The series diverges per the Alternating Series Test. F. The series converges conditionally because the corresponding series of absolute values is geometric with |r| = []$

Added by Melissa M.

Question

Please give Ace some feedback