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\frac{\sin \theta}{1 + \sec \theta} \cdot \frac{1 - \sec \theta}{1 - \sec \theta}

          \frac{\sin \theta}{1 + \sec \theta} \cdot \frac{1 - \sec \theta}{1 - \sec \theta}

(sinθ)/(1 + secθ) ·(1 - secθ)/(1 - secθ)

Added by Peggy R.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Audrey Fong

09/09/2023

Step 1

Therefore, 1 + secθ = 1 + 1/cosθ = (cosθ + 1)/cosθ and 1 - secθ = 1 - 1/cosθ = (cosθ - 1)/cosθ. Show more…

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(sin heta )/(1+sec heta )*(1-sec heta )/(1-sec heta )=, (Simplify your answer.) sin01-sec0 1+sec 01-sec0 (Simplify your answer.

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