00:01
Okay, so for part a, let's start off with the gas phase equilibrium.
00:05
So the reaction is co gas plus h2o gas converts to co2 gas and h2 gas.
00:24
So we need to calculate kp and change of r of g at 1 ,000 kelvin's.
00:32
So the equilibrium constant kp is related to the gives -free energy change by the equal.
00:42
Change in r of gives free energy is equal to negative r t times the natural log of kp so if we then we use similar similar formulas for the other species but since these entropys are not given we can proceed with the general equation for the gives free energy which is change in r of g and that is change in f of g not of c o two plus change in f change in f f of g0 of h2 minus change in f of g not of co plus change in f of g not of h2o.
01:32
So we assume constant temperature and we plug in the equations for change of rh.
01:41
So we are looking for change of r of h.
01:46
And that gives you negative 393 .93 .5 kilojoules.
01:51
Per mole plus 0 minus negative 110 .5 kilojoules per mole plus negative 241 .8 kilojoules per mole.
02:08
And you get negative 41 .2 kilojoules per mole.
02:17
Then we need to calculate kp at 298 kelvin's using the vant -hawf equation.
02:23
So the vand -hawf equation is d times the natural log of kp divided by d of 1 divided by t is equal to negative change in r of h -0 over r.
02:41
So you plug in what you know into the equation here, and you get the natural log of kp of 298 over kp of 1 ,000, as equivalent to negative 41 ,200.
02:59
Over 8 .314 times 1 over 298 minus 1 over 1 ,000.
03:15
And you end up getting 11 .71.
03:19
So in order to find the natural log of this, use the natural log of kp of 298 over kp of 1 ,000, is equal to 11 .71.
03:37
You get that equal to e 11 .71, and that gives you 1 .23 times 10 to the fifth power...