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Hello, here.
00:02
Task describes linear acceleration.
00:06
So the initial position, x1, is positive 100 meters, and the initial speed, v1, is zero meters per second.
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In the second moment, which is t2 of 20 seconds, and t1 was 0 seconds.
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So at t2, position is plus 700 meters.
00:29
And first, we have to find acceleration.
00:32
Let's do this.
00:33
Here, x as a function of time is x1 plus acceleration over 2 times t minus t1 squared.
00:42
And due to the fact that t1 is 0, that is simply x1 plus a t squared over 2.
00:49
X2 equals to x1 plus acceleration t 2 squared over 2.
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And therefore this acceleration is 2, 2 minus x1 over t2 squared which is 2 times the difference which is 600 meters and that is divided by 20 seconds squared let's complete this calculation that is 3 meters per square second now in question 2 we have to write down equation for the velocity here v x as a function of time is acceleration times time which is 3 t meters per second and now we can calculate v x at c2 so that is 3 times 20 meters per second which is 60 meters per second and in question 3 we have to find the position as a function of time here is that x is x as a function of time is x1 which is basically which is 100 meters plus acceleration t squared over 2 that is 100 meters plus 1 .50 t squared which is all 3 meters and now we have to find we have to show the graphic expression let's do this first let's choose a point at zero time this point is 100 meters and at 20 seconds that is 700 meters.
03:02
Now let's choose a point in between which is for example 10 seconds, which is which will be 250 meters.
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And now we can plot this...
