00:01
In this question we are asked to find the thavenian equivalent and norton equivalent circuit across terminal a and b.
00:08
So let's start to solve this problem.
00:11
Now first let us assume that the thavenane equivalent voltage across terminal a and b is equal to v -t -h and v -t -s is given by v -a minus v -b.
00:22
Now here if this terminal is grounded, then by using voltage division rule v -a is given by, v -a is the the voltage across 10 -oam resistance and va is given by 10 over 10 plus 13 minus wave 5 into vs.
00:43
Here vs is equal to 94 angle 30 and by simplifying this we obtained v a is equal to 39 .3367 angle 42 .264 .27 now again by using voltage division rule, voltage vb is given by voltage vb is the voltage vb is the voltage across 8 plus j 6 om impedance and vb is given by 8 plus j6 over 8 plus j6 plus 12 into 94 angle 30 and by simplifying this we obtain vb is equal to 45 .0178 angle 50 50 .17 .06 degree volt.
01:33
Now next, vts is given by va.
01:38
39 .3937 angle 42 .2647 minus vb 45 .078 angle 50 .178 angle 50 .1706.
01:56
And by simplifying this, we obtain vtx.
01:59
Is equal to 7 .74 55 angle negative 84 .655 degrees volt.
02:07
So here this is the v -th.
02:09
Now next we will calculate the feminine equivalent impedance across terminal a and b, that is z -th.
02:18
And to calculate z -t -h, we deactivate all the active elements present in the circuit, and then we find equivalent impedance across terminal a and b.
02:29
And the value of this equivalent impedance is equal to z -th.
02:34
Now in the circuit we have only one active element, that is this voltage source.
02:39
And we deactivate a voltage source by sword -circuiting it.
02:44
Now after source -circuiting this voltage source, we obtain this circuit.
02:50
Now in the circuit we will calculate total impedance across terminal a and b.
02:57
Now suppose in this circuit this is a circuit.
03:00
This is the terminal 1 and this is the terminal 2...