Question

19. Solve $2\cos(x) + 1 = 0$ on $[0, 2\pi)$. What about on $(-\pi, \pi)$? 20. Solve $\sin^2(\theta) = \cos^2(\theta)$ on $[0, 2\pi)$. 21. Solve $\sin(2\theta)\tan(\theta) = -\tan(\theta)$ on $[0, 2\pi)$.

          19. Solve $2\cos(x) + 1 = 0$ on $[0, 2\pi)$. What about on $(-\pi, \pi)$?
20. Solve $\sin^2(\theta) = \cos^2(\theta)$ on $[0, 2\pi)$.
21. Solve $\sin(2\theta)\tan(\theta) = -\tan(\theta)$ on $[0, 2\pi)$.

19. Solve 2cos(x) + 1 = 0 on [0, 2π). What about on (-π, π)?
20. Solve sin^2(θ) = cos^2(θ) on [0, 2π).
21. Solve sin(2θ)tan(θ) = -tan(θ) on [0, 2π).

Added by Lisa R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Brandon Cleary

07/12/2021

Step 1

Then, divide by 2 to get cos(x) = -1/2. Using the unit circle or reference angles, we find that the solutions for x in the interval [0,2\pi) are x = 2\pi/3 and x = 4\pi/3. Show more…

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Solve 2cos(x)+1=0 on [0,2pi ). What about on (-pi ,pi ] ? Solve sin^(2)( heta )=cos^(2)( heta ) on [0,2pi ). Solve sin(2 heta )tan( heta )=-tan( heta ) on [0,2pi ). 20.Solve sin=cos0om 0,2 21.Solve sin20tan=-tan0on [0,2