solve 30-60-90 degree trianlge FGH with short leg FG, F(7,5) and G(19), find the coordinates of the four posible points for H
Added by Brandy M.
Step 1
First, we need to find the length of the hypotenuse FH and the long leg GH. We know that in a 30-60-90 triangle, the hypotenuse is twice the length of the short leg, and the long leg is the square root of 3 times the short leg. So: FH = 2 * FG = 2 * (19 - 7) = Show more…
Show all steps
Your feedback will help us improve your experience
Avi Zellman and 63 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Multi-Step Three vertices of $\square D F G H$ are $D(-9,4), F(-1,5),$ and $G(2,0)$ Find the coordinates of vertex $H$
Polygons and Quadrilaterals
Properties of Parallelograms
$\triangle P G H$ is a $45^{\circ}-45^{\circ}-90^{\circ}$ triangle with $m \angle P=90^{\circ} .$ Find the coordinates of $P$ in Quadrant I for $G(4,-1)$ and $H(4,5)$.
Right Triangles and Trigonometry
Special Right Triangles
Give the coordinates of each point. $G, H, I, J, K,$ and $L$
Graphs, Functions, and Linear Equations
Graphs
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD